'What's the equivalent of fitdist and histfit in Python?
--- SAMPLE ---
I have a data set (sample) that contains 1 000 damage values (the values are very small <1e-6) in a 1-dimension array (see the attached .json file). The sample is seemed to follow Lognormal distribution:

--- PROBLEM & WHAT I ALREADY TRIED ---
I tried the suggestions in this post Fitting empirical distribution to theoretical ones with Scipy (Python)? and this post Scipy: lognormal fitting to fit my data by lognormal distribution. None of these works. :(
I always get something very large in Y-axis as the following:
Here is the code that I used in Python (and the data.json file can be downloaded from here):
from matplotlib import pyplot as plt
from scipy import stats as scistats
import json
with open("data.json", "r") as f:
sample = json.load(f) # load data: a 1000 * 1 array with many small values( < 1e-6)
fig, axis = plt.subplots() # initiate a figure
N, nbins, patches = axis.hist(sample, bins = 40) # plot sample by histogram
axis.ticklabel_format(style = 'sci', scilimits = (-3, 4), axis = 'x') # make X-axis to use scitific numbers
axis.set_xlabel("Value")
axis.set_ylabel("Count")
plt.show()
fig, axis = plt.subplots()
param = scistats.lognorm.fit(sample) # fit data by Lognormal distribution
pdf_fitted = scistats.lognorm.pdf(nbins, * param[: -2], loc = param[-2], scale = param[-1]) # prepare data for ploting fitted distribution
axis.plot(nbins, pdf_fitted) # draw fitted distribution on the same figure
plt.show()
I tried the other kind of distribution, but when I try to plot the result, the Y-axis is always too large and I can't plot with my histogram. Where did I fail ???
I'have also tried out the suggestion in my another question: Use scipy lognormal distribution to fit data with small values, then show in matplotlib. But the value of variable pdf_fitted is always too big.
--- EXPECTING RESULT ---
Basically, what I want is like this:
And here is the Matlab code that I used in the above screenshot:
fname = 'data.json';
sample = jsondecode(fileread(fname));
% fitting distribution
pd = fitdist(sample, 'lognormal')
% A combined command for plotting histogram and distribution
figure();
histfit(sample,40,"lognormal")
So if you have any idea of the equivalent command of fitdist and histfit in Python/Scipy/Numpy/Matplotlib, please post it !
Thanks a lot !
Solution 1:[1]
Try the distfit (or fitdist) library.
https://erdogant.github.io/distfit
pip install distfit
import numpy as np
# Example data
X = np.random.normal(10, 3, 2000)
y = [3,4,5,6,10,11,12,18,20]
# From the distfit library import the class distfit
from distfit import distfit
# Initialize
dist = distfit()
# Search for best theoretical fit on your emperical data
dist.fit_transform(X)
# Plot
dist.plot()
# summay plot
dist.plot_summary()
So in your case it would be:
dist = distfit(distr='lognorm')
dist.fit_transform(X)
Solution 2:[2]
Try seaborn:
import seaborn as sns, numpy as np
sns.set(); np.random.seed(0)
x = np.random.randn(100)
ax = sns.distplot(x)
Solution 3:[3]
I tried your dataset using Openturns library
x is the list given in you json file.
import openturns as ot
from openturns.viewer import View
import matplotlib.pyplot as plt
# first format your list x as a sample of dimension 1
sample = ot.Sample(x,1)
# use the LogNormalFactory to build a Lognormal distribution according to your sample
distribution = ot.LogNormalFactory().build(sample)
# draw the pdf of the obtained distribution
graph = distribution.drawPDF()
graph.setLegends(["LogNormal"])
View(graph)
plt.show()
If you want the parameters of the distribution
print(distribution)
>>> LogNormal(muLog = -16.5263, sigmaLog = 0.636928, gamma = 3.01106e-08)
You can build the histogram the same way by calling HistogramFactory, then you can add one graph to another:
graph2 = ot.HistogramFactory().build(sample).drawPDF()
graph2.setColors(['blue'])
graph2.setLegends(["Histogram"])
graph2.add(graph)
View(graph2)
and set the boundaries values if you want to zoom
axes = view.getAxes()
_ = axes[0].set_xlim(-0.6e-07, 2.8e-07)
plt.show()
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | Filipe |
| Solution 3 | Jean A. |





