'what is wrong incode python? [duplicate]
what is wrong in code python ?
import requests
from bs4 import BeautifulSoup
import argparse
class crtShClass():
def __init__(self,domain):
self.url = "https://crt.sh/?q=%25."+domain
self.headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:60.0) Gecko/20100101 Firefox/60.0'}
self.cookies = {}
self.foundURLsList = []
def subdomainScrape(self):
r = requests.get(self.url,headers=self.headers,timeout=10)
soup = BeautifulSoup(r.content,'html.parser')
tableRows = soup.find_all('table')[2].find_all('tr')
for row in tableRows:
try:
subdomain = row.find_all('td')[4].text
subdomain = subdomain.replace("*.","")
if subdomain not in self.foundURLsList:
self.foundURLsList.append(subdomain)
except Exception as e:
pass
def run(self):
self.subdomainScrape()
def printSubdomains(self):
for subdomain in self.foundURLsList:
print(subdomain)
parser = argparse.ArgumentParser()
parser.add_argument("-d","--domain", help="Domain Name; EX: example.com")
args = parser.parse_args()
crtsh = crtShClass(args.domain)
crtsh.run()
crtsh.printSubdomains()
in terminal by python3.. the error is : line 22 subdomain = subdomain.replace("*.","") TabError: inconsistent use of tabs and spaces in indentation
in python2.. the error is :
Traceback (most recent call last): File "certsh.py", line 2, in from bs4 import BeautifulSoup ImportError: No module named bs4
Solution 1:[1]
Just try to correct indentation like shown below:
....
try:
subdomain = row.find_all('td')[4].text
subdomain = subdomain.replace("*.","")
if subdomain not in self.foundURLsList:
self.foundURLsList.append(subdomain)
except Exception as e:
pass
...
Current version of bs4 does not support python 2
Beautiful Soup's support for Python 2 was discontinued on December 31, 2020: one year after the sunset date for Python 2 itself. From this point onward, new Beautiful Soup development will exclusively target Python 3. The final release of Beautiful Soup 4 to support Python 2 was 4.9.3.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | gremur |
