'What is the time complexity of following code:
What is the time complexity of following code:
int a = 0, i = N;
while (i > 0) {
a += i;
i /= 2;
}
Solution 1:[1]
It's complexity will be O(logn). On every iteration, value of n will be divided by 2, i.e. n + n/2 + n/4 + n/8 ... 1.
To understand logn check this out
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Shravan Mulge |
