'What is the difference between putting a 32-bit and a 64-bit register in the effective address? [duplicate]
When I assemble this (with nasm),
extern L
jmp [eax + ebx * 2 + L]
jmp [rax + rbx * 2 + L]
jmp [eax + L]
jmp [rax + L]
the result is,
67 ff a4 58 ...
ff a4 58 ...
67 ff a0 ...
ff a0 ...
There is an additional 0x67 in the resulting binary for putting a 32-bit register, but either way, at least in my program, seems to produce the same result.
Is one way just redundant, or can they sometimes produce a different result?
If they are the same, then what is a better choice?
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