'Variable as the property name in a JavaScript object literal? [duplicate]

Possible Duplicate:
How do I add a property to a Javascript Object using a variable as the name?
Use variable for property name in JavaScript literal?

Is it possible to add a variable as the property name of an object in JavaScript, like this:

var myVar = "name";
var myObject = {
    {myVar}: "value"
};
javascriptsqlalgorithmhiveqlpresto


Solution 1:[1]

Edit

With ES6, this is now possible using a ComputedPropertyName, which manifests in the form of the following syntax:

var myVar = "name";
var myObject = {
    [myVar]: "value"
};

You can use the [] syntax to use an expression as the property name (compared to the .prop and prop: value syntaxes where they are always treated as strings):

var myObject = {};
var myVar = "name";
myObject[myVar] = "value";

There is no way to use that inside an object literal, though. You have to create the object first and then assign each property separately.

Solution 2:[2]

Like this?

var myVar = "name";
var myObject = {};

myObject[myVar] = "value";

Solution 3:[3]

Yes, but not directly.

var myVar = "name";
var object = {};
object[myVar] = "value";

Solution 4:[4]

Update: I have found a way to achieve the desired output with below steps.

  1. I use array_agg with distinct. I also make an additional column start which contains the minimum value in form of an array.The output at this point will look like below.
X      A            start
dummy [1,2,3,4,5]   [1]
  1. At this point, I use reduce function of presto. I take the last element from the start and compare it with the current element of array. If the difference is <2 I update start by appending the last element of the array else I use the current element of the array and this is stored in b.
reduce(A, start, case when x - s[cardinality(s)] < 2 then s || s[cardinality(s)] else s || x end, s-> s) as b

The final output shall be like below.

X      A            start   b
dummy [1,2,3,4,5]   [1]     [1,1,3,3,5]
  1. Next step is obvious, we simply explode b after using array_distinct and join with proper conditions.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Maciej Bledkowski
Solution 2 Blender
Solution 3 Niet the Dark Absol
Solution 4 mw981

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