'Unable to retrieve siblings using xpath axes

XML

<list>
<item attribute="type1" class="one" description=""/>
<item attribute="type2" class="two" description=""/>
<item attribute="type1" class="three" description=""/>
<item attribute="type3" class="four" description=""/>
<item attribute="type3" class="five" description=""/>
.
.
</list>

What I want to is, create a list of all the types ie (type1, type2, type3 .. and so on like this..) Type1 Type2 Type3

and generate a table corresponding to each type. eg. Type1 {all items listed here which has attribute type1}

I also want to add navigate buttons in each table that takes the user to other tables. eg. I can move from Type2 table to Type1 table if I hit previous button and Type3 table if I hit next button.

So far, I have generated the list and tables using key() and generate-id() But I am unable to add navigation links. Any leads would be helpful

Edit: I can't show the whole code, here is some portion for idea

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:key name="types" select="/list/item/@attribute" use="."/>

<xsl:template match="/">
<head> MY WORK </head>
<body>
<xsl:apply-templates/>
</body>  
</xsl:template>

<div id="main_table" class="section">
        
    <!-- Template createlist displays all type names with links to Table -->
        <xsl:call-template name="createlist">
        </xsl:call-template>
</div>

<xsl:call-template name="list_all_tables"/>


        <!--template that creates list-->
        <xsl:template name="createlist">
        <xsl:for-each select="/list/item/@attribute[generate-id()= generate-id(key('types',.)[1])]">
            
                    <h3><a href="{concat('#',generate-id(.))}"><xsl:value-of select="."/></a></h3>
        </xsl:for-each>
        </xsl:template>

        <!--template that creates list tables one by one -->
        <xsl:template name="list_all_tables">
        <xsl:for-each select="/list/item/@attribute[generate-id()= generate-id(key('types',.)[1])]">
    
            <div class="section" id="{generate-id(.)}">

            <!-- 'Previous Section' and 'Next Section' buttons -->
                <!--want to create a template navigate that adds links -->
            <xsl:call-template name="navigate"/>
    
            <h1><a name="{generate-id(.)}"><xsl:value-of select="."/></a></h1>

                <!--another template that creates table for a particular type-->
            <xsl:call-template name="create_table">
            <xsl:with-param name="attributeName" select="."/>
            </xsl:call-template>

                </div>
    
        </xsl:for-each>
        </xsl:template>

<xsl:template name="create_table">
<xsl:param name="attributeName"/>

    <xsl:variable name="item"
               select="/list/items[ @attribute=$attributeName]"/>
     <table class="toc">
               <tbody>
        <xsl:apply-templates select="$item" mode="tab"/>
               </tbody>
     </table>

</xsl:template>

<xsl:template match="item" mode="tab">

    <tr>
            <td class="first">
              <a href="{concat('#',generate-id(.))}"><xsl:value-of select="@class"/></a>
           </td>
           <td><xsl:value-of select="@description"/></td>
    </tr>
</xsl:template>

<xsl:template name="navigate">

    <span class="navigate">
        <a>
            <xsl:if test="position()!=1">
                <xsl:attribute name="href">
                    <xsl:value-of select="concat('#',generate-id(preceding-sibling::*[name(.) = name(current())]))"/>
                </xsl:attribute>
            </xsl:if>
            <xsl:text>Previous Section</xsl:text>
        </a>
        <a>
            
                <xsl:if test="position()!=last()">
                    <xsl:attribute name="href">
                    <xsl:value-of select="concat('#',generate-id(following-sibling::*[name(.) = name(current())]))"/>
                    </xsl:attribute>
                </xsl:if>
                
            <xsl:text>Next Section</xsl:text>
        </a>
    </span>

</xsl:stylesheet>

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source

'Unable to retrieve siblings using xpath axes

Sources

Related Questions