Unable to print correct character using INT 10H

Question

I have recently tried to make a simple bootloader to learn more about the 8086 Intel CPU. Along the way, I needed a way to print characters to screen. However, when I try to execute the following instructions, I get 'b' instead of 'a' in the QEMU output console.

[bits 16]
[org 0x7c00]

%macro read_sector 6
    pusha
    mov ah, 02H
    mov dl, %1
    mov dh, %2
    mov ch, %3
    mov cl, %4
    mov al, %5
    mov bx, %6
    int 13H
    jc error
    popa
%endmacro%

%macro get_cursor_pos 0
    push ax
    push bx
    
    mov ah, 03H
    mov bh, 0
    int 10H
    
    pop ax
    pop bx
%endmacro%

%macro set_cursor_pos 0
    pusha

    mov ah, 02H
    mov bh, 0
    int 10H

    popa
%endmacro%

mov bp, 0x89B8
mov sp, bp

mov al, 97
loop:
    mov ah, 0AH
    mov bh, 0
    mov cx, 1
    int 10H
    inc al
    ;cmp al, 98
    ;jl loop
end:
    hlt

print_ch:
    pusha
    
    mov ah, 0AH
    mov bh, 0
    mov cx, 1
    int 10H

    ; cmp al, 10
    ; je handle_newline

    ; get_cursor_pos modifies registers dh, dl
    ; get_cursor_pos
    ; inc dl
    ; set_cursor_pos
end_putch:
    popa
    ret

error:
    hlt
handle_newline:
    add dh, 1
    mov dl, 0
    set_cursor_pos
    jmp end_putch

times 510 - ($ - $$) db 0
dw 0xaa55

But, If I add a jmp $ before inc al, QEMU console shows 'a' as output.

I have no idea about any mistakes in my code. Any help is welcome!