The != statement in the while loop is returning True even when it shouldn't - Python

Question

In the password function, I am trying to make the user enter a password and if he/she inputs the wrong password, then give them another chance to write the correct password or just simply quit. The problem which I am facing is if I enter the wrong password, and then if i use TRY AGAIN, then even if I write the correct password(i.e, 1234), it still says INCORRECT PASSWORD!

To check what was wrong, I used print(answer, type(answer)) and print(passwd, type(passwd)) to see if they were actually the exact same or not (which they were btw). I also used print(answer != passwd) to see if this was causing the issue and it was. It is returning True even after both answer and passwd are equal. Please suggest what I should do.

passwd = '1234'


def password():
    global passwd
    answer = input("ENTER THE PASSWORD:\t")
    print(answer, type(answer))
    print(passwd, type(passwd))
    while answer != passwd:
        print(answer != passwd)
        print('INCORRECT PASSWORD!')
        print("1. TRY AGAIN.\n2. QUIT")
        ans = input("Answer(1/2):\t")
        while ans not in ['1', '2']:
            print("Incorrect input.")
            ans = input("Answer(1/2):\t")
        if ans == '1':
            password()
        elif ans == '2':
            print("Bye!")
            quit()

Answer 1

passwd = '1234'
# I added answer = None for the first function call
answer = None              


def password():
    global passwd
    # The global answer ensures I use whatever the latest value of answer is(defined by the return statement at teh end of function)
    global answer         
    answer = input("ENTER THE PASSWORD:\t")
    print(answer, type(answer))
    print(passwd, type(passwd))
    while answer != passwd:
        print(answer != passwd)
        print('INCORRECT PASSWORD!')
        print("1. TRY AGAIN.\n2. QUIT")
        ans = input("Answer(1/2):\t")
        while ans not in ['1', '2']:
            print("Incorrect input.")
            ans = input("Answer(1/2):\t")
        if ans == '1':
            password()
        elif ans == '2':
            print("Bye!")
            quit()
    # This would return the answer and change the global variable
    return answer          


password()

Answer 2

Personnaly speaking, your main problem was the order of using while loops. I have managed to solve your problem with the password function by editing your code and changing the order of while loops and some other stuff:

passwd = '1234'
def password():
    global passwd
    while True:
        answer = input("ENTER THE PASSWORD:\t")
        if answer != passwd:
          wrongAnswer = input("1. TRY AGAIN.\n2. QUIT\nAnswer(1/2):\t")
          while wrongAnswer != "1" and wrongAnswer != "2":
            print("Incorrect input.")
            wrongAnswer = input("Answer(1/2):\t")
          if wrongAnswer == "2":
            print("Bye!")
            break
        else:
          print("Password is correct! Goodby")
          break

Example output

ENTER THE PASSWORD: 8765
1. TRY AGAIN.
2. QUIT
Answer(1/2):    1
ENTER THE PASSWORD: 8765
1. TRY AGAIN.
2. QUIT
Answer(1/2):    1
ENTER THE PASSWORD: 1234
Password is correct! Goodby

Answer 3

You have to include an else statement or answer == passwd

passwd = '1234'


def password():
    global passwd
    answer = input("ENTER THE PASSWORD:\t")
    print(answer, type(answer))
    print(passwd, type(passwd))
    while answer != passwd:
        print(answer != passwd)
        print('INCORRECT PASSWORD!')
        print("1. TRY AGAIN.\n2. QUIT")
        ans = input("Answer(1/2):\t")
        while ans not in ['1', '2']:
            print("Incorrect input.")
            ans = input("Answer(1/2):\t")
        if ans == '1':
            password()
        elif ans == '2':
            print("Bye!")
            quit()
    else:
        print('correct')