SwiftUI: use Link with onTapGesture

Question

I want to specify a Link in my SwiftUI view, but I also want to register when/if that Link was actually tapped or not. What's the best way to do this? I tried adding an onTapGesture on the Link (which is a View I believe):

Link("Test", destination: URL(string: "testThreePanel://")!)
                    .onTapGesture {
                        print("Testing button link tapped")
                    }

But the onTapGesture doesn't get invoked on tapping the link.

Is there another way to do this?

Answer 1

you could try this, works for me, but only on iOS15 / macOS12:

// iOS15 / macOS12 only 
Link("Test", destination: URL(string: "https://duckduckgo.com")!)
        .environment(\.openURL, OpenURLAction { url in
            print("---> testing link actioned")
            return .systemAction
        })

Answer 2

For iOS 15 it also works if you remove the 'url' parameter, just in case you don't want to use it.

Link("Test", destination: URL(string: "https://duckduckgo.com")!)
.environment(\.openURL, OpenURLAction { _ in
                print("---> testing link actioned")
                return .systemAction
            })