'Swift convert 'Character' to 'Unicode.Scalar'
I'm trying to filter non-alphabetical characters out of a String, but running into the issue that CharacterSet uses Unicode.Scalar and String consists of Character.
Xcode gives the error:
Cannot convert value of type 'String.Element' (aka 'Character') to specified type 'Unicode.Scalar?'
let name = "name"
let allowedCharacters = CharacterSet.alphanumerics
let filteredName = name.filter { (c) -> Bool in
if let s: Unicode.Scalar = c { // cannot convert
return !allowedCharacters.contains(s)
}
return true
}
Solution 1:[1]
CharacterSet has an unfortunate name inherited from Objective C. In reality, it is a set of Unicode.Scalars, not of Characters (“extended grapheme clusters” in Unicode parlance). This is necessary, because while there is a finite set of Unicode scalars, there is an infinite number of possible grapheme clusters. For example, e + ?? + ?? + ?? ... ad infinitum is still just one cluster. As such, it is impossible to exhaustively list all possible clusters, and it is often impossible to list the subset of them that has a particular property. Set operations such as those in the question must use scalars instead (or at least use definitions derived from the component scalars).
In Swift, Strings have a unicodeScalars property for operating on the string a the scalar level, and the property is directly mutable. That enables you to do things like this:
// Assuming...
var name: String = "..."
// ...then...
name.unicodeScalars.removeAll(where: { !CharacterSet.alphanumerics.contains($0) })
Solution 2:[2]
A single Character can consist of several UnicodeScalars, so you need to iterate through all of them and check if they are contained in CharacterSet.alphanumerics.
let allowedCharacters = CharacterSet.alphanumerics
let filteredName = name.filter { (c) -> Bool in
return !c.unicodeScalars.contains(where: { !allowedCharacters.contains($0)})
}
Test input: let name = "asd?1"
Test output: "asd1"
Solution 3:[3]
Without var or double-negatives:
let filteredName = String(name.unicodeScalars.filter {
CharacterSet.alphanumerics.contains($0)
})
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | Dávid Pásztor |
| Solution 3 |
