'swagger: file path in path parameter
Here is my api requirement
GET http://localhost:8080/filePath/{path}
For example:
curl http://localhost:8080/filePath/home/users/user/one.txt
Here is yaml config:
parameters:
- name: path
in: path
description: Todo description
type: string
required: true
But I'm getting 404 error. How can I use file path in path parameter?
Solution 1:[1]
OpenAPI 2.0 (Swagger 2.0), 3.0, and 3.1 do not allow you to use slashes in path parameters, so you can't do that. There's an open feature request for this:
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Helen |
