'Substring is not working as expected if length is greater than length of String

I know if/else works, but I needed an alternative.

I am using

B = String.Concat(A.Substring(0, 40));

to capture the first 40 characters of a value.

If the value at A is more than 40, B is able to capture, but if the value of A is less than 40, there is no value being captured at B.

c++sharp.netregexstring


Solution 1:[1]

Quick and dirty:

  A.Length > 40 ? A.Substring(0, 40) : A

Solution 2:[2]

Create an extension for it... Call it Truncate or Left, or whatever.

public static class MyExtensions
{
    public static string Truncate(this string s, int length)
    {
        if(s.Length > length) 
            return s.Substring(0, length);
        return s;
    }
}

Then you can simply call it like so:

string B = A.Truncate(40);

Also note that you don't have to make it an extension method, although it would be cleaner.

In your StringTool class:

public static string Truncate(string value, int length)
{
    if(value.Length > length) 
        return value.Substring(0, length);
    return value;
}

And to call it:

string B = StringTool.Truncate(A, 40);

Solution 3:[3]

Use the below code to substring.

B = String.padright(40).Substring(0, 40)).Trim()

Solution 4:[4]

Extensions are best for problems like this one ;)

Mine have some dirty name, but everyone knows what it would do - this is an exception-safe substring:

public static string SubstringNoLongerThanSource(this string source, int startIndex, int maxLength)
{
    return source.Substring(startIndex, Math.Min(source.Length - startIndex, maxLength));
}

Solution 5:[5]

B = string.Concat(A.Substring(0, Math.Min(40, A.Length)));

Solution 6:[6]

You can use Left from Microsoft.VisualBasic.Strings.

B = Microsoft.VisualBasic.Strings.Left(A, 40);

I don't know why you want to use Concat, anyway.

Solution 7:[7]

Another method using Take

B = new string(A.Take(40).ToArray())

Or extension method

public static string Left(this string value, int count)
{
    return new string(value.Take(count).ToArray());
}

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Me.Name
Solution 2 Peter Mortensen
Solution 3 Peter Mortensen
Solution 4 Peter Mortensen
Solution 5 irfandar
Solution 6 Peter Mortensen
Solution 7

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