'SQLAlchemy engine.connect() fails for Snowflake using keypair authentication
My goal is to be able to write a pandas dataframe to Snowflake using the to_sql() function. I am able to successfuly query from Snowflake using read_sql() with no problems. It appears that to_sql() requires a slightly different configuration I can't figure out. I've tried two different approaches that I've outlined below.
I'm guessing, but could be wrong that the keypair authentication seems to be the problem. When I remove the private key parameter in both approaches, I get an error that the password is missing, rather than the particularly unclear errors I get otherwise. Perhaps not having the password specified is short circuiting the attempt and I really have another problem.
Alternately, if there is a better way to write an entire pandas dataframe to Snowflake I'm happy to entertain other options.
Method 1 Snowflake Connector
edit: it appears that sqllite is the only database supported if the connection isn't a SQLAlchemy connection.
This approach fails with DatabaseError: Execution failed on sql 'SELECT name FROM sqlite_master WHERE type='table' AND name=?;': not all arguments converted during string formatting
import snowflake
conn = snowflake.connector.connect(
account=acct,
warehouse=wh,
database=db,
schema=sc,
user=usr,
private_key=pkb,
)
df.to_sql('TABLENAME', con=conn, if_exists='replace', index=False)
Method 2 - SQLAlchemy Engine
I've found documentation on how to use a private key with SQLAlchemy. However, it fails with ValueError: Invalid IPv6 URL on the call to engine.connect()...
from snowflake.sqlalchemy import URL
from sqlalchemy import create_engine
engine = create_engine(URL(
account=acct,
warehouse=wh,
database=db,
schema=sc,
user=usr,
connect_args={
'private_key': pkb,
}
))
with engine.connect() as conn:
df.to_sql('TABLENAME', con=conn, if_exists='replace', index=False)
The traceback for both these errors are very long, but I'm happy to post them if it would help troubleshoot.
Solution 1:[1]
I don't know what is wrong with #2, but I found out that combining #1 and #2 will work...
import snowflake.connector
from sqlalchemy import create_engine
conn = snowflake.connector.connect(
account=acct,
warehouse=wh,
database=db,
schema=sc,
user=usr,
private_key=pkb,
)
engine = create_engine(f"snowflake://{acct}.snowflakecomputing.com", creator=lambda: conn)
try:
with engine.connect() as c:
# Note: the table name MUST be all lowercase for some reason, even though Snowflake uses all caps
df.to_sql('TABLENAME'.lower(), con=c, if_exists='replace', index=False)
finally:
engine.dispose()
conn.close()
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Dave Novelli |
