'split(regexp_replace ) Like Function In Presto : 331
Is there any way to split values based on consecutive 0's in presto.Minimum 6 digits should be there in first split, if digit count is less than 6 than need to consider some 0's as digit then split if digit count is >= 6 then just need to split in 2 groups. below query is working as expected in Hive.But I am not able to do the same using presto.
select low as orginal_Value,
split(regexp_replace(low,'(\\d{6,}?)(0+)$','$1|$2'),'\\|') Output_Value from test;
Presto Query:
presto> SELECT regexp_split('1234567890000', '(\d{6,}?)(0+)$') as output;
output
[1234567890000]
(1 row)
Solution 1:[1]
It worked Now.
select split(regexp_replace('1234567890000','(\d{6,}?)(0+)$','$1|$2'), '|') as output;
enter code here
output
-------------------
[123456789, 0000]
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Sonu |

