'split function does not return any observations with large dataset
I have a dataframe like this:
seqnames pos strand nucleotide count
id1 12 + A 13
id1 13 + C 25
id2 24 + G 10
id2 25 + T 25
id2 26 + A 10
id3 10 + C 5
But it has more than 100,000 rows in total, seqnames has 3138 levels. I would like to split it into lists of dataframes according to seqnames, so I used split function:
data_list <- split(data,data$seqnames)
But it only returns something like this:
List of 3138
$ id1:'data.frame': 0 obs. of 6 variables:
..$ seqnames : Factor w/ 3138 levels "id1","id2",..:
..$ pos : int(0)
..$ strand : Factor w/ 3 levels "+","-","*":
..$ nucleotide: Factor w/ 8 levels "A","C","G","T",..:
..$ count : int(0)
..$ sample_id : chr(0)
$ id2:'data.frame': 0 obs. of 6 variables:
..$ seqnames : Factor w/ 3138 levels "id1","id2",..:
..$ pos : int(0)
..$ strand : Factor w/ 3 levels "+","-","*":
..$ nucleotide: Factor w/ 8 levels "A","C","G","T",..:
..$ count : int(0)
..$ sample_id : chr(0)
I can't figure out why it is like this because I have used it on a made up dataframe with all numbers (of course, not as many rows as this one) and it works. How can I solve this problem?
Solution 1:[1]
It is just that there are many unused levels as the column 'seqnames' is a factor. With split, there is an option to drop (drop = TRUE - by default it is FALSE) to remove those list elements. Otherwise, they will return as data.frame with 0 rows. If we want those elements to be replaced by NULL, then find those elements where the number of rows (nrow) are 0 and assign it to NULL
data_list <- split(data,data$seqnames)
> str(data_list)
List of 5
$ id1:'data.frame': 2 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 1 1
..$ pos : int [1:2] 12 13
..$ strand : chr [1:2] "+" "+"
..$ nucleotide: chr [1:2] "A" "C"
..$ count : int [1:2] 13 25
$ id2:'data.frame': 3 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 2 2 2
..$ pos : int [1:3] 24 25 26
..$ strand : chr [1:3] "+" "+" "+"
..$ nucleotide: chr [1:3] "G" "T" "A"
..$ count : int [1:3] 10 25 10
$ id3:'data.frame': 1 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 3
..$ pos : int 10
..$ strand : chr "+"
..$ nucleotide: chr "C"
..$ count : int 5
$ id4:'data.frame': 0 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..:
..$ pos : int(0)
..$ strand : chr(0)
..$ nucleotide: chr(0)
..$ count : int(0)
$ id5:'data.frame': 0 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..:
..$ pos : int(0)
..$ strand : chr(0)
..$ nucleotide: chr(0)
..$ count : int(0)
Doing the assignment to NULL
data_list[sapply(data_list, nrow) == 0] <- list(NULL)
-check again
> str(data_list)
List of 5
$ id1:'data.frame': 2 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 1 1
..$ pos : int [1:2] 12 13
..$ strand : chr [1:2] "+" "+"
..$ nucleotide: chr [1:2] "A" "C"
..$ count : int [1:2] 13 25
$ id2:'data.frame': 3 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 2 2 2
..$ pos : int [1:3] 24 25 26
..$ strand : chr [1:3] "+" "+" "+"
..$ nucleotide: chr [1:3] "G" "T" "A"
..$ count : int [1:3] 10 25 10
$ id3:'data.frame': 1 obs. of 5 variables:
..$ seqnames : Factor w/ 5 levels "id1","id2","id3",..: 3
..$ pos : int 10
..$ strand : chr "+"
..$ nucleotide: chr "C"
..$ count : int 5
$ id4: NULL
$ id5: NULL
data
data <- structure(list(seqnames = structure(c(1L, 1L, 2L, 2L, 2L,
3L), .Label = c("id1",
"id2", "id3", "id4", "id5"), class = "factor"), pos = c(12L,
13L, 24L, 25L, 26L, 10L), strand = c("+", "+", "+", "+", "+",
"+"), nucleotide = c("A", "C", "G", "T", "A", "C"), count = c(13L,
25L, 10L, 25L, 10L, 5L)), row.names = c(NA, -6L), class = "data.frame")
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | akrun |
