'Sort integer file names in Python

I have file names as

enter image description here

When I iterate over them, it iterated in a string manner like:

1
10 
11
.
.
19
2
20
.. so on. I hope you got this. 

I want to iterate them over as integers not strings. Please help me write a function for it.

for i,file in enumerate(sorted(files),key=lambda x: int(os.path.splitext(file)[0]))
     #CODE 

But gives an error:

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-45-f667164b9d6e> in <module>
     
----> 6 for i,file in enumerate(sorted(files),key=lambda x: int(os.path.splitext(file)[0])):
     

TypeError: 'key' is an invalid keyword argument for enumerate()

Please help me write a function for it. Thanks in advance.



Solution 1:[1]

files = ['0.pdf', '1.pdf', '12.pdf', '15.pdf', '3.pdf', '2.pdf' ]
fileDict= {}
SortedFiles = []
for i in range(len(files)):
    fileDict[int(files[i].split('.')[0])] = files[i]
for i in sorted(list(fileDict.keys())):
    SortedFiles.append(fileDict[i])
print (SortedFiles)

['0.pdf', '1.pdf', '2.pdf', '3.pdf', '12.pdf', '15.pdf']

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Mohammed Hijaz