'Setup resource health alert for multiple storage accounts
So the idea is to create resource health alert for multiple storage accounts using terraform. It's fairly simple for one storage account as one would pass the value
output "id" {
description = "Id of the storage account created."
value = azurerm_storage_account.storage.id
}
to the resource_id or hardcode the resource id with the resource actual id. But my ask here is how I can setup one single alert block for all the storage accounts provisioned by the terraform. I have been trying to use the above data block but the name variable would take only strings. Please provide a sample example as to how you would do it.
locals {
activity_log_alerts = {
resource_health_alerts= {
environment = var.environment
resource_group_name = var.rgp
enabled = "true"
** scopes = module.main.storage_account_name["storage_name"] **
alert_name = “Resource health alert for storage accounts”
description = format(“The state of the azure resource is unknown”}
category = "ResourceHealth"
level = "Critical"
operation_name = null
resource_health = [
{
current = ["Unknown"]
previous = ["Available"]
reason = ["PlatformInitiated"]
}
]
The error I received is this: Error: Null value found in list
scopes = tolist([var.resource_id])
UPDATE: Another Approach With this approach I was hoping to get all the resource under the same RG and subscription but got the same error
data "azurerm_subscription" "current" {
subscription_id = var.subscription_id
}
locals {
activity_log_alerts = {
resource_health_alerts= {
environment = var.environment
resource_group_name = var.rgp
enabled = "true"
scopes = [data.azurerm_subscription.current.id]
alert_name = “Resource health alert for storage accounts”
description = format(“The state of the azure resource is unknown”}
category = "ResourceHealth"
level = "Critical"
operation_name = null
resource_health = [
{
current = ["Unknown"]
previous = ["Available"]
reason = ["PlatformInitiated"]
}
]
The error I received is this: Error: Null value found in list
scopes = tolist([var.resource_id])
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|
