'Sending strings over Serial to Arduino
I'm currently experimenting with sending a string to my Arduino Yun and trying to get it to reply back depending on what I send it.
I picked up a framework of some code here and have been experimenting with it but apart from the serial monitor displaying 'ready' I can't make it go any further.
The code is:
//declace a String to hold what we're inputting
String incomingString;
void setup() {
//initialise Serial communication on 9600 baud
Serial.begin(9600);
while(!Serial);
//delay(4000);
Serial.println("Ready!");
// The incoming String built up one byte at a time.
incomingString = "";
}
void loop () {
// Check if there's incoming serial data.
if (Serial.available() > 0) {
// Read a byte from the serial buffer.
char incomingByte = (char)Serial.read();
incomingString += incomingByte;
// Checks for null termination of the string.
if (incomingByte == '\0') {
// ...do something with String...
if(incomingString == "hello") {
Serial.println("Hello World!");
}
incomingString = "";
}
}
}
Can anyone point me in the right direction?
Thanks
Solution 1:[1]
I suspect the problem is that you're adding the null terminator onto the end of your string when you do: incomingString += incomingByte. When you're working with string objects (as opposed to raw char * strings) you don't need to do that. The object will take care of termination on its own.
The result is that your if condition is effectively doing this: if ("hello\0" == "hello") .... Obviously they're not equal, so the condition always fails.
I believe the solution is just to make sure you don't append the byte if it's null.
Solution 2:[2]
Try This:
String IncomingData = "";
String Temp = "";
char = var;
void setup()
{
Serial.begin(9600);
//you dont have to use it but if you want
// if(Serial)
{
Serial.println("Ready");
}
//or
while(!Serial)
{delay(5);}
Serial.println("Ready");
void loop()
{
while(Serial.available())
{
var = Serial.read();
Temp = String(var);
IncomingData+= Temp;
//or
IncomingData.concat(Temp);
// you can try
IncomindData += String(var);
}
Serial.println(IncomingData);
IncomingData = "";
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Peter Bloomfield |
| Solution 2 | Dani Bresler |
