'Save first word in files names in another file
I have a folder that has lots of files with the format name1_name2_xxxx.xlsx. I want to save name1 of each file in this folder in a new text file
I tried this but it's not working, any advice?
import os
for filename in os.listdir("/my_dir/")
n=os.path.basename(filename)
nn=n.split("_")
nnn=n[1]
print(n)
Solution 1:[1]
- You should use " instead of “
- To get the first item from a list use [0] and not [1]
- You don't need
os.path.basename,os.listdir()already returns just the files name as string.
Other than that it seems okay to me, now you just have to save it to a file:
import os
with open("names_file.txt", "w", encoding="utf-8") as f:
for filename in os.listdir("/my_dir/")
base_name = filename.split("_")[0]
print(base_name)
f.write(filename+"\n")
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | ewz93 |
