'Running 7-Zip from within a Powershell script

I'm trying to use 7-Zip to backup some files inside a Powershell (v2) script.

I have:

$zipPath = "C:\Program Files\7-Zip\7z.exe"
[Array]$zipArgs = "-mx=9 a", "`"c:\BackupFolder\backup.zip`"", "`"c:\BackupFrom\backMeUp.txt`""

&$zipPath $zipArgs;

But when I run this I get:

7-Zip [64] 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18


Error:
Incorrect command line

Writing this to the screen I get:

C:\Program Files\7-Zip\7z.exe -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"

So I assumed that I needed to put quotes around the path to 7z.exe, that gave me:

$zipPath = "C:\Program Files\7-Zip\7z.exe"
$zipPath = " `"$zipPath`" "
[Array]$zipArgs = "-mx=9 a", "`"c:\BackupFolder\backup.zip`"", "`"c:\BackupFrom\backMeUp.txt`""

&$zipPath $zipArgs;

But then I get the following error:

    The term '"C:\Program Files\7-Zip\7z.exe"' is not recognized as the name of a cmdlet, function, script file
, or operable program. Check the spelling of the name, or if a path was included, verify that the path is c
orrect and try again.
At C:\BackupScript\Backup.ps1:45 char:22
+                     & <<<< `"$zipPath`" $zipArgs;                    
    + CategoryInfo          : ObjectNotFound: ("C:\Program Files\7-Zip\7z.exe":String) [], CommandNotFound 
   Exception
    + FullyQualifiedErrorId : CommandNotFoundException

Writing it out gives me:

"C:\Program Files\7-Zip\7z.exe" -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"

Which works as expected when pasting straight into a command window. I have been trying to figure this out for a while, but assume I am missing something (probably quite obvious). Can anybody see what I need to do to make this run?

powershell 7zip

Solution 1:^[1]

put "&" special character before 7z command. Example: &7z ...

Solution 2:^[2]

Simply prefix the command with an ampersand

& "C:\Program Files\7-Zip\7z.exe" -mx=9 a "c:\BackupFolder\backup.zip" "c:\BackupFrom\backMeUp.txt"

Solution 3:^[3]

Maybe a simpler solution is to run 7-zip on your Powershell via cmd:

cmd /c 7za ...

Solution 4:^[4]

If you adapt it correctly: Dont forget the "" on "$Target" and avoid $7zipPath in c:\programm files with a space in the path

Set-Alias 7zip $7zipPath

$Source = "c:\BackupFrom\backMeUp.txt"
$Target = "c:\BackupFolder\backup.zip"

7zip a -mx=9 "$Target" "$Source"

7z a "$ArchiveName" -t7z '@listfile.txt'

Solution 5:^[5]

try to use parameter -file to specify the location of program or script:

-file "C:\Program Files\someting.exe"

Solution 6:^[6]

C:\'Program files'\7-Zip\7z.exe a '$archiveFile'  -Path '$dest'

where:

archiveFile = name of the archive file name.
dest = destination folder.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Ric
Solution 2	OldBuildingAndLoan
Solution 3	Lars Bilke
Solution 4	EPO
Solution 5	trezor
Solution 6	the Tin Man

'Running 7-Zip from within a Powershell script

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Solution 4:[4]

Solution 5:[5]

Solution 6:[6]