Return array of objects with respect to uniqueness of property: Javascript

Question

I am having array of objects with the following structure

const arr = [
              {id: 0, name: "abc", userid: "0"},
              {id: 1, name: "lmn", userid: "123"},
              {id: 3, name: "pqr", userid:"456"},
              {id: 4, name: "xyz", userid: "123"}
            ]

I want to return the objects where userid should be unique and is not equals to "0".

This is my approach. It returns just everything

   const result = [
        ...new Set(
             arr.map((node) => {
            if (node.userid !== "0") return node;
          })
        )
      ];
      console.log(result);

Answer 1

Maybe that might me done in a more short-hand way, but it works this way:

const arr = [
          {id: 0, name: "abc", userid: "0"},
          {id: 1, name: "lmn", userid: "123"},
          {id: 3, name: "pqr", userid: "456"},
          {id: 4, name: "xyz", userid: "123"}
        ];

const clearZero = arr.filter((obj) => obj.id != 0);
const finalArray = [];

clearZero.forEach((obj) => {
  if (finalArray.every((elem) => elem.userid !== obj.userid)) {
    finalArray.push(obj);
  }
})

console.log(finalArray); // logs out no. 1 and no.3