replace string in xslt 2.0 with replace function

Question

I have a string like this

"My string"

Now I want to replace my with best so that the output will be like best string. I have tried some thing like this

 <xsl:value-of select="replace( 'my string',my,best)"/>

but probably its a wrong syntax

I have googled a lot but found nothing..every where the mechanism to do this XSLT 1.0 is explained.Can any one tell me how to do it in XSLT 2.0 ,The easy way compared to 1.0

Answer 1

Given:

<xsl:variable name="s1" select="'My string'"/>

Simply use:

<xsl:value-of select="replace($s1, 'My', 'best')"/>

Note that a regular expression is applied. Meaning:

<xsl:value-of select="replace('test.replace', '.', ':')"/>

Becomes:

::::::::::::

Be sure to escape the characters that have special meaning to the regular expression interpreter:

<xsl:value-of select="replace('test.replace', '\.', '::')"/>

Becomes:

test::replace

Answer 2

First check, if your xslt processor (saxxon) is the latest release. Then you have to set <xsl:stylesheet version="2.0" in the head of your xslt-stylesheet. That's it. Your code was fine, besides you forgot the apostrophs:

<xsl:value-of select="replace( 'my string',my,best)"/>

must be

<xsl:value-of select="replace('my string','my','best')"/>