Regex get string not include double quotes python

Question

I am working on a web scrapper and I have a js string like this.

Package Title: ('"id"', ':', '1', ',', '"title"', ':', '"', '11 Dofollow and 500 Words Article')
Package Title: ('"id"', ':', '2', ',', '"title"', ':', '"', 'Basic Page and Privacy Policy Page')
Package Title: ('"id"', ':', '3', ',', '"title"', ':', '"', '2x Standart Page')

I want to like this, how can I do this?

11 Dofollow and 500 Words Article
Basic Page and Privacy Policy Page
2x Standart Page

I tried this but not working

package = re.findall(r'\'^[^"](.*?)^[^"]\'',str(jsstring))
print(package)