Regex for website or url validation [duplicate]

Question

I know this is so common question & there are so many answers for this, but my problem is different, I want to accept the URL with all below formats:

http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com

// & much more ...

So here idea is, I am allowing the user to enter there website & another user can just click on the saved website & go to users website. So here it's not a good idea to restrict the user to input proper URL, they can enter any of the above formats. Here is the regex I am using right now, but that only checks if URL starts from proper protocol:

^(ftp|http|https):\/\/[^ "]+$

Answer 1

You can try this:

^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?\/?$

Updated Demo

const regex = /^((ftp|http|https):\/\/)?(www.)?(?!.*(ftp|http|https|www.))[a-zA-Z0-9_-]+(\.[a-zA-Z]+)+((\/)[\w#]+)*(\/\w+\?[a-zA-Z0-9_]+=\w+(&[a-zA-Z0-9_]+=\w+)*)?\/?$/gm;
const str = `http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com
www.sample.com
mofiz.com
kolim.com
www.murikhao.www.sample.com
http://murihao.www.sample.com
http://www.sample.com/xyz?abc=dkd&p=q&c=2
www.sample.gov.bd
www.sample.com.en
www.sample.vu
www.sample.u/


`;
let m;

while ((m = regex.exec(str)) !== null) {

    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    console.log("matched :"+m[0]);
}