'Regex for a extracting a string starting with a particular word and ending with a year

INPUT 1: The string is enclosed CASE NO.: Appeal (civil) 648 of 2007 in between.

OUTPUT 1: Appeal (civil) 648 of 2007

INPUT 2: The string is enclosed CASE NO.: Appeal (civil) 6408 of 2007 in between.

OUTPUT 2: Appeal (civil) 6408 of 2007

I want to extract the string starting with the word CASE NO.(Case Insensitive) and ending with the year being the second occurrence of a number.

I have tried the following code.

case_no = re.search(r'(?=Case No)(\w+\W+)*?\b\d{4}\b', contents, re.IGNORECASE)
    if case_no:
        print(case_no.group(0))

Solution 1:^[1]

I would use a lazy dot here to match the nearest year occurring after CASE NO.:

inp = "The string is enclosed CASE NO.: Appeal (civil) 6408 of 2007 in between."
m = re.search(r'\bCASE NO\.:\s*(.*\b\d{4}\b)', inp)
print(m.group())  # Appeal (civil) 6408 of 2007

Solution 2:^[2]

inp = "The string is enclosed CASE NO.: Appeal (civil) 6408 of 2007 in between."
case_no = re.search(r'(?=Case No)(\w+\W+)*?\d+(\w+\W+)*?\b\d{4}\b', inp, re.IGNORECASE)
print(case_no.group())

Sources

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Solution	Source
Solution 1
Solution 2	surajsuresh29

'Regex for a extracting a string starting with a particular word and ending with a year

Solution 1:[1]

Solution 2:[2]

Sources

Related Questions

Solution 1:^[1]

Solution 2:^[2]