'reading behind from list

import numpy as np

filename = 'input1.txt'
output_file = 'output.txt'
delimiters = ',.?!'

with open(filename, 'r') as f:
    text = f.read()
for delimiter in delimiters:
    text = text.replace(delimiter, ',')
lines = text.split('\n')
parts = list()
print(lines)

I want all the lines containing text / numbers from the back to be in the sheet

example I have an input.text file

1,2,3,4,5,6
7,8,9,10,11,12
13,14,15,16,17

this give me

['1,2,3,4,5,6', '7,8,9,10,11,12', '13, 14,15,16,17 ',' ',' ',' ', '', '', '', '', '']

I'm looking for an exit from behind to read the lines

['13, 14,15,16,17', '7,8,9,10,11,12', '1,2,3,4,5,6', '', '', '', '', '', '', '']

Thank you for your help



Solution 1:[1]

Reverse a list in Python:

print(list('abc')[::-1])
> ['c', 'b', 'a']

Your case:

import numpy as np
import re
filename = 'input1.txt'
output_file = 'output.txt'
text = re.sub('[.?!]', ',', text)

with open(filename, 'r') as f:
    text = f.read()
text = re.sub('[.?!]', ',', text)

lines = text.split('\n')[::-1]
parts = []
print(lines)

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Anton Frolov