'RabbitMQ always hold 1 message on queue

I want to always hold one message on rabbitMQ's queue. When the second message is published first message will be consumed but the second message wait in a queue. When the third message is published the second message will be consumed. This is how things will go but I don't know how to do it. Any ideas?

Note: I am using c#

c++sharprabbitmq


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