R: How to delete ID from a list of multiple strings in a longitudinal format

Question

I had an earlier post regarding how to delete ID if any of the rows within ID contain certain strings (e.g., A or D) from the following data frame in a longitudinal format. These are R code examples that I received from the earlier post (r2evans, akrun, ThomasIsCoding) in order:

1. d %>% group_by(id) %>% filter(!any(dx %in% c("A", "D"))) %>% ungroup()
2. filter(d, !id %in% id[dx %in% c("A", "D")])
3. subset(d, !ave(dx %in% c("A", "D"), id, FUN = any))

While these all worked well, I realized that I had to remove more than 600 strings (e.g., A, D, E2, F112, G203, etc), so I created a csv file for the list of these strings without a column name. 1. Is it the right approach to make a list? 2. How should I modify the above R codes if I intend to use the file of the strings list? Although I reviewed the other post or Google search results, I could not figure out what to do with my case. I would appreciate any suggestions!

Data frame:

id   time   dx
1     1     C
1     2     B
2     1     A
2     2     B
3     1     D
4     1     G203
4     2     E1

The results I want:

id    time  dx
 1     1     C
 1     2     B

UPDATE: Tarjae's below answer resolved the issue. The following are R codes for the solution.

my_list <- read.csv("my_list.csv")

columnname
    A
    D
    E2
    F112
    G203

1. d %>% group_by(id) %>% filter(!any(dx%in%my_list$columnname)) %>% ungroup()
2. filter(d, !id %in% id[dx %in% my_list$columnname])
3. subset(d, !ave(dx %in% my_list$columnname, id, FUN = any))