Python Program wont ever return "True"

Question

So, I am working on this programming project, and these are the instructions for the project:

A list is sorted in ascending order if it is empty or each item except the last one is less than or equal to its successor. Define a predicate isSorted that expects a list as an argument and returns True if the list is sorted, or returns False otherwise. (Hint: For a list of length 2 or greater, loop through the list and compare pairs of items, from left to right, and return False if the first item in a pair is greater.)

This is what I made:

def isSorted(lst):  
  for x in range(len(lst) - 1):     
     if(lst[x] > lst[x + 1]):     
            return False    
            return True
# Testing
print(isSorted([]))
print(isSorted([1,2,3,4,5]))
print(isSorted([1,2,3,6,5]))

And these are the results I get: My Program

I cant figure our why I don't get "True" as a result for the third line in the "Testing" part of the program. Any help would be greatly appreciated!

Edit: I tried unindenting the return true

portion of the program, but now i get back the following error:

File <string>, line 5
    return True
     ^
SyntaxError: 'return' outside function 

Answer 1

As commented, the second if statement being indented on the same level is "dead code"

You can rewrite your loop and return statements using all()

def isSorted(lst):  
  return all(lst[x] < lst[x + 1] for x in range(len(lst) - 1))

Answer 2

Should be better like this

def isSorted(lst):  
  for x in range(len(lst) - 1):     
    if(lst[x] > lst[x + 1]):     
      return False    
  return True