Python open and save Excel file. Do I need to state sleep time?

Question

My Excel file when opened will need 30 seconds to load data from a database. My script below successfully Open, Wait till data fully loaded then Save and Close Excel file one by one.

So my question is: Does python by default must wait till the workbook is fully load before it move to the next command Save(). And then wait until Save() is completed to execute Close(). I don't mind to put time.sleep(10) but I want to know how python processes the command sequence in this case.

(When I do parsing data from web, I need to command Python to wait for a certain element is loaded. That's why I wonder if I need to instruct Python to do the same with Excel.)

files  = ['file1','file2']

path = f'C:\\Users\\Myfolder\\'

import win32com.client as win32
excel = win32.gencache.EnsureDispatch('Excel.Application')
excel.Visible = True

for i in files:
    print(i)
    wb = excel.Workbooks.Open( path + str(i)+'.xlsx')
    # time.sleep(25)

    for wb_name in excel.Workbooks:           #list all currently open excel file
        if wb_name.Name ==  str(i)+'.xlsx' :  #Save exact file name
            print("Save workbook:",wb_name.Name)
            wb_name.Save()
            wb_name.Close()