Python - If > 16 and for in dictionary list comprehension

Question

I need to make a function that returns a dictionary where values are doubled if values from previous dictionary are bigger than 10

def dbl(d1):
    d = {x: d1.get(x, 0) * 2 for x in set(d1)}
    return d

This is my code that doubles. I can't figure out where to put if > 10

My try:

a = {"a": 1, "b": 17, "c": 15} 

def dbl(d1):
    d = {x: d1.get(x, 0) * 2 for x in set(d1) if x > 10}
    return d

TypeError: '>' not supported between instances of 'str' and 'int'

Answer 1

Any item in set(d1) gives you one of dictionary keys ("a", "b", "c"), not dictionary values. Try to put if d1[x] > 10 instead of if x > 10

Answer 2

Using dict comprehension you can do is as follows :

def dbl(d1):
    d = {k:v*2  if v>10 else v for (k,v) in d1.items()}
    return d

This solution permits to keep the value that are < 10 and double the ones that are > 10.