'Python - I'm making a hangman game, and nothing gets updated

So pretty much it's in the title. Once you type a letter in it returns the same thing from the beginning. I'm new to python and I don't know that much about it, I've tried finding a solution to it here already but was unsuccesful. I don't think it's very complicated so I hope someone can figure out what is wrong.

import random

HANGMAN = (
    """

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""",
    """

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|    O
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""",
    """

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|    O
|   -+-
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""",
    """


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|    O
|  /-+-
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""",
    """

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|    O
|  /-+-/
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""",
    """

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|    O
|  /-+-/
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""",
    """

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|  /-+-/
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""",
    """

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|  /-+-/
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""")

MAX_WRONG = len(HANGMAN) - 1

WORDS = ("WAREHOUSE", "HINGE", "SPOON", "WALLET", "GRATE", "POCKET", "REINDEER", "NILE", "POISON", "LEGEND", "SAXOPHONE",
"CIRCUS", "SILO", "FLOOD", "DISH", "SCANDAL", "FRAME", "CAFE")

word = random.choice(WORDS)  

guessed = "-" * len(slowo)

wrong = 0

used = []

print("Welcome to Hangman!'.\n WARNING! Type all the letters in uppercase")

while wrong < MAX_WRONG and guessed != word:
    print(HANGMAN[wrong])  
    print("\nYou used these letters already:\n", used)
    print("\nYou guessed these many so far:\n", guessed)

    guess = input("\n\nType in a letter: ")
    guess = guess.upper()

    while guess in used:  
        print("You've already used: ", guess)
        guess = input("Wprowadź literę: ")
        guess = guess.upper()

used.append(guess)

if guess in word:
    print("\nGood Job!", guess, "is in the hidden word!")

    new = ""
    for i in range(len(word)):
        if guess == word[i]:
            new += guess
        else:
            new += guessed[i]
    guessed = new

else:
    print("\nLetter: ", guess, "isn't featured in the hidden word.")
    wrong += 1

if wrong == MAX_WRONG:
    print(HANGMAN[wrong])
    print("\nYou died...")
else:
    print("\nCongratulations! You guessed the hidden word!")

print("\The hidden word was: ", word)

input('\n\nTo end the process, press ENTER.')

That's it, if you've run the code you may've seen that it just returns

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You used these letters already: []

You guessed these many so far:



Solution 1:[1]

I had to learn a little bit of Polish to walk through what was happening, but it looks like this section of code needs to be indented so that it is in the first while block:

uzyte.append(traf)

if traf in slowo:
    print("\nBrawo!", traf, "znajduje si? w ukrytym s?owie!")

    nowy = ""
    for i in range(len(slowo)):
        if traf == slowo[i]:
            nowy += traf
        else:
            nowy += odgadniete[i]
    odgadniete = nowy

else:
    print("\nLitera: ", traf, "nie wyst?puje w ukrytym s?owie.")
    zle += 1

if zle == MAX_ZLE:
    print(WISIELEC[zle])
    print("\nNie ?yjesz...")
else:
    print("\nGratulacje! Odgad?e? ukryte s?owo!")

Result:

Wykorzysta?e? ju? nast?puj?ce litery:
 ['A', 'B', 'C', 'D', 'E', 'F', 'G']

Na razie odgad?e? tyle liter:
 --A-A


Wprowad? liter?: h

Litera:  H nie wyst?puje w ukrytym s?owie.

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Nie ?yjesz...
>>> 

Here's a working example of the (now translated) while block:

while wrong < MAX_WRONG and guessed != word:
    print(HANGMAN[wrong])
    print("\nYou used these letters already:\n", used)
    print("\nYou guessed these many so far:\n", guessed)

    guess = input("\n\nType in a letter: ")
    guess = guess.upper()

    while guess in used:
        print("You've already used: ", guess)
        guess = input("Wprowad? liter?: ")
        guess = guess.upper()

    used.append(guess)

    if guess in word:
        print("\nGood Job!", guess, "is in the hidden word!")

        new = ""
        for i in range(len(word)):
            if guess == word[i]:
                new += guess
            else:
                new += guessed[i]
        guessed = new

    else:
        print("\nLetter: ", guess, "isn't featured in the hidden word.")
        wrong += 1

    if wrong == MAX_WRONG:
        print(HANGMAN[wrong])
        print("\nYou died...")
    else:
        print("\nCongratulations! You guessed the hidden word!")

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1