Python : easy way to do geometric mean in python?

Question

I wonder is there any easy way to do geometric mean using python but without using python package. If there is not, is there any simple package to do geometric mean?

Answer 1

In case someone is looking here for a library implementation, there is gmean() in scipy, possibly faster and numerically more stable than a custom implementation:

>>> from scipy.stats import gmean
>>> gmean([1.0, 0.00001, 10000000000.])
46.415888336127786

Compatible with both Python 2 and 3.*

Answer 2

Starting Python 3.8, the standard library comes with the geometric_mean function as part of the statistics module:

from statistics import geometric_mean

geometric_mean([1.0, 0.00001, 10000000000.]) # 46.415888336127786

Answer 3

just do this:

numbers = [1, 3, 5, 7, 10]


print reduce(lambda x, y: x*y, numbers)**(1.0/len(numbers))

Answer 4

Here's an overflow-resistant version in pure Python, basically the same as the accepted answer.

import math

def geomean(xs):
    return math.exp(math.fsum(math.log(x) for x in xs) / len(xs))

Answer 5

you can use pow function, as follows :

def p(*args):
    k=1
    for i in args:
        k*=i
    return pow(k, 1/len(args))]

>>> p(2,3)
2.449489742783178

Answer 6

You can also calculate the geometrical mean with numpy:

import numpy as np
np.exp(np.mean(np.log([1, 2, 3])))

result:

1.8171205928321397

Answer 7

Geometric mean

import pandas as pd
geomean=Variable.product()**(1/len(Variable))
print(geomean)

Geometric mean with Scipy

from scipy import stats
print(stats.gmean(Variable))