Python Dict: Keep first column , and make the rest as nested dict

Question

Given the following dict:

mydict={'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}

I would like to transform this dictionary into a nested dict, where "id" key is kept, but all other (arbitary) keys are then packed into a nested dict. Hence the output should be like:

nestdict={'id':'123','data':{'name': 'Bob', 'age': '30','city': 'LA'}}

What I have tried was using dict.pop but this returns a list , and also using defaultdict from collections, but this did not work.

from collections import defaultdict
nestdict = defaultdict(dict)
nestdict[mydict['id']] = mydict[['name'],['age'],['city']]
nestdict

Answer 1

If you don't want to mutate the original mydict,

>>> mydict = {'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}
>>> d = {'id': mydict['id'], 'data': {k: v for k, v in mydict.items() if k != "id"}}
{'id': '123', 'data': {'name': 'Bob', 'age': '30', 'city': 'LA'}}

If mutating mydict (since we pop out id) is OK,

>>> mydict = {'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}
>>> d = {'id': mydict.pop('id'), 'data': mydict}
{'id': '123', 'data': {'name': 'Bob', 'age': '30', 'city': 'LA'}}

Answer 2

You can make a copy of your dictionary to preserve the original one:

temp_dict = mydict.copy()
temp_dict.pop('id')
nested_dict = {'id': mydict['id'], 'data': temp_dict}
print(nested_dict)

The output:

{'id': '123', 'data': {'name': 'Bob', 'age': '30', 'city': 'LA'}}