Python detect string and int using exception handling

Question

I am trying to work on detecting strings and int using exception handling and cannot figure it out. Please help!

Using the inputs

• Lee 18
• Lua 21
• Mary Beth 19
• Stu 33
• -1

    parts = input().split()
    name = parts[0]

    while name != '-1':

    # FIXME: The following line will throw ValueError exception.
    #        Insert try/except blocks to catch the exception.
    try:
        age = int(parts[1]) + 1
        print('{} {}'.format(name, age))
        parts = input().split()
        name = parts[0]
        if age != 0:
            raise ValueError(0)
    except ValueError as excpt:
        name = parts[0]
        age = excpt

The result of the code above is:

• Lee 19
• Lua 22

When I am trying to get the code to result with:

• Lee 19
• Lua 22
• Mary 0
• Stu 34

Please assist!

Answer 1

I figured this one out messing with it for a while solution code

# Split input into 2 parts: name and age
parts = input().split()
name = parts[0]
while name != '-1':
    # FIXME: The following line will throw ValueError exception.
    #        Insert try/except blocks to catch the exception.
    try:
        age = int(parts[1]) + 1
        print('{} {}'.format(name, age))
        parts = input().split()
        name = parts[0]
        if age == 'Beth':
            age = 0
            
    except ValueError as excpt:
        age = 0
        print('{} {}'.format(name, age))
        parts = input().split()
        name = parts[0]

Answer 2

try:
    age = int(parts[1]) + 1
    print('{} {}'.format(name, age))
    parts = input().split()
    name = parts[0]
        
except ValueError as excpt:
    age = 0
    print('{} {}'.format(name, age))
    parts = input().split()
    name = parts[0]