'Python - Automatically adjust width of an excel file's columns
Newbie - I have a Python script that adjusts the width of different columns of an excel file, according to the values specified:
import openpyxl
from string import ascii_uppercase
newFile = "D:\Excel Files\abc.xlsx"
wb = openpyxl.load_workbook(filename = newFile)
worksheet = wb.active
for column in ascii_uppercase:
if (column=='A'):
worksheet.column_dimensions[column].width = 30
elif (column=='B'):
worksheet.column_dimensions[column].width = 40
elif (column=='G'):
worksheet.column_dimensions[column].width = 45
else:
worksheet.column_dimensions[column].width = 15
wb.save(newFile)
Is there any way through which we can adjust the width of every column to its most optimum value, without explicitly specifying it for different columns (means, without using this "if-elif-elif-......-elif-else" structure)? Thanks!
Solution 1:[1]
for col in worksheet.columns:
max_length = 0
column = col[0].column_letter # Get the column name
for cell in col:
try: # Necessary to avoid error on empty cells
if len(str(cell.value)) > max_length:
max_length = len(str(cell.value))
except:
pass
adjusted_width = (max_length + 2) * 1.2
worksheet.column_dimensions[column].width = adjusted_width
This could probably be made neater but it does the job. You will want to play around with the adjusted_width value according to what is good for the font you are using when viewing it. If you use a monotype you can get it exact but its not a one-to-one correlation so you will still need to adjust it a bit.
If you want to get fancy and exact without monotype you could sort letters by width and assign each width a float value which you then add up. This would require a third loop parsing each character in the cell value and summing up the result for each column and probably a dictionary sorting characters by width, perhaps overkill but cool if you do it.
Edit: Actually there seems to be a better way of measuring visual size of text: link personally I would prefer the matplotlib technique.
Hope I could be of help, my very first stackoverflow answer =)
Solution 2:[2]
Updated version as of openpyxl 3.0.0 (using .columns fails with TypeError: expected <class 'str'>:
for column_cells in ws.columns:
length = max(len(str(cell.value)) for cell in column_cells)
ws.column_dimensions[column_cells[0].column_letter].width = length
Solution 3:[3]
With the latest openpyxl you can use this:
from openpyxl.utils import get_column_letter
for idx, col in enumerate(worksheet.columns, 1):
worksheet.column_dimensions[get_column_letter(idx)].auto_size = True
Solution 4:[4]
I have a problem with merged_cells and autosize not work correctly, if you have the same problem, you can solve adding the next lines inside code of oldsea
for col in worksheet.columns:
max_length = 0
column = col[0].column # Get the column name
for cell in col:
if cell.coordinate in worksheet.merged_cells: # not check merge_cells
continue
try: # Necessary to avoid error on empty cells
if len(str(cell.value)) > max_length:
max_length = len(cell.value)
except:
pass
adjusted_width = (max_length + 2) * 1.2
worksheet.column_dimensions[column].width = adjusted_width
Solution 5:[5]
Based on the comment above and add this post openpyxl - adjust column width size. I succeeded, but the answer should be:
from openpyxl.utils import get_column_letter
for col in ws.columns:
max_length = 0
column = get_column_letter(col[0].column) # Get the column name
# Since Openpyxl 2.6, the column name is ".column_letter" as .column became the column number (1-based)
for cell in col:
try: # Necessary to avoid error on empty cells
if len(str(cell.value)) > max_length:
max_length = len(cell.value)
except:
pass
adjusted_width = (max_length + 2) * 1.2
ws.column_dimensions[column].width = adjusted_width
i'm using openpyxl = "^3.0.5"
Solution 6:[6]
def auto_format_cell_width(ws):
for letter in range(1,ws.max_column):
maximum_value = 0
for cell in ws[get_column_letter(letter)]:
val_to_check = len(str(cell.value))
if val_to_check > maximum_value:
maximum_value = val_to_check
ws.column_dimensions[get_column_letter(letter)].width = maximum_value + 1
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Naofumi |
| Solution 2 | Nam G VU |
| Solution 3 | Corvax |
| Solution 4 | Community |
| Solution 5 | HK boy |
| Solution 6 | freddiemacintosh |
