'Prometheus : how do i sum by with 2 different metrics
I have 2 different metrics : metric_a with a field type metric_b with a field type (same one)
I'm trying to summarise a and b, of the same type. If type exists only on metric_a and not on metric_b - it should return metric_b's result. I've tried a lot of options on prometheus:
sum by (type)(metric_a{job=~"provision-dev"}) or vector(0) + sum by(type)(metric_b{job=~"provision-dev"}) or vector(0) : returns only the values from metric_a, and doesn't calculate metric_b's results.
sum by (type)(metric_a{job=~"provision-dev"}) + sum by(type)(metric_b{job=~"provision-dev"}) : returns only the values from metric_b, and doesn't calculate metric_a's results.
sum by (cluster_id)(provision_scale_out_failures{job=~"provision-dev"} + provision_scale_out_success{job=~"provision-dev"}) : well this isn't even a right query
Basically here's an example of a success :
metric_a :
- type = type_1, sum = 5
- type = type_2, sum = 2
metric_b :
- type = type_1, sum = 4
- type = type_3, sum = 3
result of the query :
- type = type_1, sum = 9
- type = type_2, sum = 2
- type = type_3, sum = 3
Solution 1:[1]
This is the expected behavior when using a binary operator: both side must have a matching label set to be taken into account.
If you want to be able to aggregate both side and get the single one, you first must get the union of different metrics using the __name__ label:
sum by(__name__,type)(metric_a{job=~"provision-dev"}) or on(__name__) sum by(__name__,type)(metric_b{job=~"provision-dev"})
You can cascade the aggregation operator:
sum by (type) (sum by (__name__,type)(metric_a{job=~"provision-dev"}) or on(__name__) sum by(__name__,type)(metric_b{job=~"provision-dev"}))
Finally, you can also compact everything into:
sum by (type) ({__name__=~"metric_a|metric_b",job=~"provision-dev"})
Solution 2:[2]
The following PromQL query should sum metric_a and metric_b by type:
(sum(metric_a) by (type) + sum(metric_b) by (type))
or
(sum(metric_a) by (type) unless sum(metric_b) by (type))
or
(sum(metric_b) by (type) unless sum(metric_a) by (type))
How it works:
- The
sum(metric_a) by (type) + sum(metric_b) by (type)sums time series with matchingtypelabel values on both sides of+according to matching rules - The
sum(metric_a) by (type) unless sum(metric_b) by (type)returnssum(metric_a) by (type)results fortypelabel values missing insum(metric_b) by (type). See docs aboutunlessoperator. - The
sum(metric_b) by (type) unless sum(metric_a) by (type)returnssum(metric_a) by (type)results fortypelabel values missing insum(metric_a) by (type).
Then results from these three queries are joined with or operator.
This query is equivalent to the query proposed by Michael: sum({__name__=~"metric_a|metric_b"}) by (type) .
P.S. This query can be simplified further when using MetricsQL:
sum(metric_a, metric_b)
This query works, since sum() function in MetricsQL accepts and sums arbitrary number of arguments.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | valyala |
