Print a numerical triangle [duplicate]

Question

You are given a positive integer (example: N = 6). Print a numerical triangle of height like the one below:

1
22
333
4444
55555 

Use no more than two lines of code. Use a for loop and print function only. You can't use anything related to strings. N is an input.

What I tried:

for i in range(1,int(input())):
    print(*range(1, i+1))

my output:

1
1 2
1 2 3
1 2 3 4

Answer 1

One way to get the triangle indicated (without using strings) is to treat the output as numbers and to calculate those numbers:

N = 6
for i in range(1, N):
    print(sum(10**j for j in range(i)) * i)

Output as requested.

Answer 2

You can use list multiplication, list unpacking and print's capability of taking multiple arguments and outputting them separated by sep to produce the correct output:

for i in range(1, int(input())):
    l = [i] * i
    print(*l, sep="")

Or on two lines:

for i in range(1, int(input())):
    print(*[i] * i, sep="")

Answer 3

Tell whoever left this assignment you did it in one line and no strings used:

be careful what you wish for

_ = [print((10**i  - 1)//9 * i) for i in range(1, 6)]

if you hate math:

_ = [[print(i, end='' if j != i-1 else '\n') for j in range(i)] for i in range(1, 6)]

Personally I prefer this one for this assignment:

_ = [print(i*int(bin((1 << i) - 1)[2:])) for i in range(1, 6)]

Answer 4

You can use

for i in range(1,int(input())):
    print(str(i)*i) 

Answer 5

This will help you.

edit: Now without using string function.

n = 6 # write you value here.
for a in range(1,n):
    print(f'{a}'*a)

Answer 6

Your code must be

for i in range(1, int(input())+1):
    print(*[i for j in range(i)])

Answer 7

Here is one function that works.

def f(n): a='' for i in range(1,n): a=a+'1' print(i*int(a))