Print 2 lists side by side

Question

I'm trying to output the values of 2 lists side by side using list comprehension. I have an example below that shows what I'm trying to accomplish. Is this possible?

code:

#example lists, the real lists will either have less or more values
a = ['a', 'b', 'c,']
b = ['1', '0', '0']

str = ('``` \n'
       'results: \n\n'
       'options   votes \n'
       #this line is the part I need help with: list comprehension for the 2 lists to output the values as shown below
       '```')

print(str)

#what I want it to look like:
'''
results:

options  votes
a        1
b        0
c        0
''' 

Answer 1

You can use the zip() function to join lists together.

a = ['a', 'b', 'c']
b = ['1', '0', '0']
res = "\n".join("{} {}".format(x, y) for x, y in zip(a, b))

The zip() function will iterate tuples with the corresponding elements from each of the lists, which you can then format as Michael Butscher suggested in the comments.

Finally, just join() them together with newlines and you have the string you want.

print(res)
a 1
b 0
c 0

Answer 2

This works:

a = ['a', 'b', 'c']
b = ['1', '0', '0']

print("options  votes")

for i in range(len(a)):
    print(a[i] + '\t ' + b[i])

Outputs:

options  votes
a        1
b        0
c        0

Answer 3

from __future__ import print_function  # if using Python 2

a = ['a', 'b', 'c']
b = ['1', '0', '0']

print("""results:

options\tvotes""")

for x, y in zip(a, b):
    print(x, y, sep='\t\t')

Answer 4

[print(x,y) for x,y in zip(list1, list2)]

Note the square brackets enclosing the print statement.