'Populate bash array with any amount of arguments

I'm trying to fill an array in my script by passing the content directly to the script:

bash ./script.sh arg1 arg2 arg3

I know that I can address these arguments with $1, $2 and so on but the array doesn't always have the same amount of items in it which is why I can't really do:

databases=($1 $2 $3)

I'd imagine that I could use a loop but I don't know how to loop through all passed arguments.

arraysbashargumentsscript


Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source

Related Questions