Parsing gerrit query json output in python (multiple entries)

Question

I am running a gerrit query with a regex in "intopic" via python. This basically returns multiple gerrit reviews.

Here is the script snippet:

   cmd_string="ssh -p 29418 username@my_gerrit_server.net gerrit query --current-patch-set --format=JSON branch:master intopic:{my_reviews_*}"
   child = pexpect.spawn(cmd_string)
   child.delaybeforesend = 1
   child.expect(r'Enter passphrase for key(.*?):', timeout=10)
   child.sendline(passwd)
   child.expect (r'(.*?)$')
   cmd_op = child.read(size=-1)
   json_dict = json.loads(cmd_op)

The step at json.loads fails. The cmd_op looks something like this:

{"project":"prj1","branch":"master".... , "subject":"review1",...    }
{"project":"prj2","branch":"master".... , "subject":"review2",...    }
{"type":"stats","rowCount":2,"runTimeMilliseconds":31,"moreChanges":false}

I am looking to read some value from each of the above review entry to do some further processing

This doesnt look like a valid json format as entries are not comma separated. Is there any alternate way i could fetch/process this data?

Running on Ubuntu with Python 2.7.12

Thanks in advance,

Answer 1

First of all, there are some minor errors in the code.

1. Inlcude necessary headers.
2. Use std:: namespace prefix.

#include <iostream>
#include <string>
#include <cctype>

void convert(std::string &s){
    for (int i =0; i < s.length(); i++){
        s[i] = std::toupper(s[i]);
    }
}

int main(){
    std::string name;
    std::cout << "Enter your name: ";
    std::getline(std::cin, name);
    convert(name);
    std::cout << name << std::endl;
    return 0;
}

Using pointer version?

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cctype>
#define SIZE 100

void convert(char *s, size_t size){
    for (int i =0; i < size; i++){
        s[i] = std::toupper(s[i]);
    }
}

int main(){
    char name[SIZE];
    std::cout << "Enter your name: ";
    std::fgets(name, SIZE, stdin);
    convert(name, strlen(name));
    std::cout << name << std::endl;
    return 0;
}

Another version using pointers

#include <iostream>
#include <string>
#include <cctype>

void convert(std::string *s){
    for (int i =0; i < s -> length(); i++){
        (*s)[i] = std::toupper((*s)[i]);
    }
}

int main(){
    std::string *name = new std::string();
    std::cout << "Enter your name: ";
    std::getline(std::cin, *name);
    convert(name);
    std::cout << *name << std::endl;

    delete name;
    return 0;
}