only files names in .7z using python

Question

I am reading .7z file and want to extract only files name with extension. I want abc.txt only. right now I am doing split with "\" and getting last right of (\) and then checking (.) in it and it is not full proof. Is there any better way using python? or If I have a string how can I check if this is a valid file in OS without using OS library.

        7z gives hierarchical path for folder.

        parent folder
        parent folder\child folder
        parent folder \child folder\abc.txt

    with py7zr.SevenZipFile(folder_location, 'r') as archive:
        file_paths_reports = archive.getnames()

        for file_rep in file_paths_reports:
            print(file_rep)
            # how can I check if this is a file in a folder?