Matrix Solver If statement

Question

So I was programming this Matrix Solver and the only problem i had with it, how to find out what cells are next to me and if they are clear. So I found this long if and or statement and wanted to know, what it execatly means since the rest of the code is very simple. Or if there is an easier way to check the cells which are near you.

grid = [[0, "S", 0, 0, 0, 1],
        [1, 1, 0, 0, 0, 1],
        [0, 0, 0, 1, 0, 0],
        [0, 1, 1, 0, 0, 1],
        [0, 1, 0, 0, 1, 0],
        [0, 1, 2, 0, 0, 0]]


def move(x, j):
    if grid[x][j] == 2:
        print('found at %d,%d' % (x, j))
        return True
    elif grid[x][j] == 1:
        print ('wall at %d,%d' % (x, j))
        return False
    elif grid[x][j] == 3:
        print ('visited at %d,%d' % (x, j))
        return False


    print( 'visiting %d,%d' % (x, j))
    grid[x][j] = 3
    

 #Look to the cells next to your current cell
    if ((x < len(grid)-1 and move(x+1, j))
        or (j > 0 and move(x, j-1))
        or (x > 0 and move(x-1, j))
        or (j < len(grid)-1 and move(x, j+1))):
        return True
        
    return False


def find(m):
    for x in range(len(m)):
        for j in range(len(m[0])):
            if m[x][j] == "S":
                return x, j

x,j = find(grid)

move(x, j)