loop through a list of objects with utc and remove the object with oldest utc java

Question

I have a list like below

"pList": [
   {
    "Utc": "2021-12-20T05:10:20+0000",
    "key": {
     "num": "23131"
    }
   },
   {
    "Utc": "2021-12-20T05:15:20+0000",
    "key": {
     "num": "23131"
    }
   },
   {
    "Utc": "2021-12-20T05:20:20+0000",
    "key": {
     "num": "23131"
    }
   }
  ]

now , i need to loop through this list and delete the oldest utc. How do i achieve this in java ? (List should contain 2 items at given instance. I need to look for the oldest utc item and remove it from the list)

This is what i have tried

if(pList.size() > 2) {

                   for(int i = 1; i < pList.size() ; i++ ) {
                     Instant prior = pList.get( i - 1 ).Utc();
                        Instant current = pList.get( i ).Utc();
                        if(prior.isBefore(current)) {
                            pList.remove(i);
                        }
                   }
                   
                  }

Answer 1

Here's how i implemented it,

                  if(pList.size() > 2) {
                   for(int i = 1; i < pList.size() ; i++ ) {
                     Instant prior = pList.get( i - 1 ).getUtc();
                        Instant current = pList.get( i ).getUtc();
                        if(prior.isBefore(current)) {
                            pList.remove(i-1);
                        }
                   }
                  }

It made sure that pList has only 2 items at given instance and removed the oldest if there's a new item coming into the list.