'Kotlin's JvmDefault - still need to declare the method ?
I am building my Spring Boot 1.5 + Kotlin 1.2.41 project into a jar. One of the interfaces in the jar has the @JvmDefault and it compiles fine with the flag (if I remove the flag, it fails).
Now, I am trying to use this interface in another java project, in which I define the Kotlin project as a dependency.
In one implementing class, I don't override the default method. Intellij seems to be OK with it, as it doesn't complain. However, when I compile with Maven, I get :
[ERROR] attempting to assign weaker access privileges; was public
If I implement the method (with some dummy implementation), then it compiles... but it defeats the purpose of the default interface.
Any idea what could be wrong ?
When opening the Kotlin interface code from the java project, here's the decompiled code I see :
public interface CrawlerOutput {
@kotlin.jvm.JvmDefault public open fun finalize(): kotlin.Unit { /* compiled code */ }
public abstract fun output(analyzedRepository: com.myCompany.Repository): kotlin.Unit
}
My java code implementing the interface :
public class CsvOutput implements CrawlerOutput {
@Override
public void output(Repository repository) throws IOException {
log.info("own output is receiving some data !");
}
/**
* IF I REMOVE BELOW METHOD, MAVEN CAN'T COMPILE IT ANYMORE,
* COMPLAINING OF WEAKER ACCESS PRIVILEGE
*/
@Override
public void finalize(){
}
}
Am I missing something ?
Thanks
Vincent
Solution 1:[1]
Android Studio and JVM always update its versions. As a result of that some of you may experience this error message.
Inheritance from an interface with '@JvmDefault' members is only allowed with -Xjvm-default option
Don't worry . The solution is very simple. Just add below code part to the end of android block of your app level build.gradle file and sync.
tasks.withType(org.jetbrains.kotlin.gradle.tasks.KotlinCompile).configureEach {
kotlinOptions {
freeCompilerArgs += [
"-Xjvm-default=all",
]
}
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Revan siddappa |
