JS list of dictionaries, get first value by condition

Question

Given a list of dictionaries in JS, I want to get the first one that is enabled and not deleted.

The dictionary will look like this:

objects= [{'name':'a', 'width': 100, 'deleted': true, 'enabled': true},
          {'name':'b', 'width': 200, 'deleted': false, 'enabled': false},
          {'name':'c', 'width': 300, 'deleted': false, 'enabled': true},
          {'name':'d', 'width': 400, 'deleted': true, 'enabled': true},

I used to take the first one by using objects[0] but now I need to tkae the deleted and enabled in consideration. How can I get the first relevant value? so the results should be {'name':'c', 'width': 300, 'deleted': false, 'enabled': true}

Answer 1

Find Method

You can use the Array.find method to find the first element that matches a given condition.

const solution = objects.find(o => o.enabled && !o.deleted);