'Javascript Date - set just the date, ignoring time?

I have a bunch of objects, each of which has a timestamp, that I want to group by date, into a JSON object. The ultimate goal is something like this:

myObject = {
    "06/07/2012" : [ 
        {
            "timestamp" : "07/06/2012 13:30",
            ...
        },
        {
            "timestamp" : "07/06/2012 14:00",
            ...
        }
    ],
    "07/07/2012 [...]
}

To get the date, I'm testing each timestamp object and using:

var visitDate = new Date(parseInt(item.timestamp, 10));
visitDate.setHours(0);
visitDate.setMinutes(0);
visitDate.setSeconds(0);

..then I'm using that to store as a name for the JSON object. It seems messy, and I'm sure there should be an easier way of doing things.

Advice / suggestions welcomed!!

javascript date

Solution 1:^[1]

How about .toDateString()?

Alternatively, use .getDate(), .getMonth(), and .getYear()?

In my mind, if you want to group things by date, you simply want to access the date, not set it. Through having some set way of accessing the date field, you can compare them and group them together, no?

Check out all the fun Date methods here: MDN Docs

Edit: If you want to keep it as a date object, just do this:

var newDate = new Date(oldDate.toDateString());

Date's constructor is pretty smart about parsing Strings (though not without a ton of caveats, but this should work pretty consistently), so taking the old Date and printing it to just the date without any time will result in the same effect you had in the original post.

Solution 2:^[2]

If you don't mind creating an extra date object, you could try:

var tempDate = new Date(parseInt(item.timestamp, 10));
var visitDate = new Date (tempDate.getUTCFullYear(), tempDate.getUTCMonth(), tempDate.getUTCDate());

I do something very similar to get a date of the current month without the time.

Solution 3:^[3]

var today = new Date();
var year = today.getFullYear();
var mes = today.getMonth()+1;
var dia = today.getDate();
var fecha =dia+"-"+mes+"-"+year;
console.log(fecha);

Solution 4:^[4]

let date = new Date((new Date("07/06/2012 13:30")).toDateString())
console.log(date)

Solution 5:^[5]

Date handling is unavoidably tricky. First off, you will save a lot of trouble if you send datetimes as UTC ISO strings ("yyyy-MM-dd hh:mm:ss.000Z"). If you're storing dates as strings, store them as ISO strings. Parsing dates with slashes is locale dependent and so error prone. (Europeans put the day first, americans the month.)

To get a date string from a datetime ISO string, use myDatetimeString.substring(0,10). To get a date object from a date string, just add the zeros...

myUtcMidnightDateObject = new Date( myDateString + ' 00:00:00Z' )

To then format your UTC midnight date object, use toLocaleString() with the UTC option...

myFormattedDate = myUtcMidnightDateObject.toLocaleDateString({},{ timeZone: "UTC" })

Much more detail can be found here.

Solution 6:^[6]

Just split the local date string to array by "/" and arrange them to accordingly,very simple.

var date=new Date();
var datearray=date.toLocaleString().split("/");
var sqldate= datearray[2].slice(0,4)+"-"+(datearray[0]<=9?"0"+datearray[0]:datearray[0])+"-"+(datearray[1]<=9?"0"+datearray[1]:datearray[1]);

Solution 7:^[7]

new Date().toISOString().split('T')[0]

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1
Solution 2
Solution 3	Charlie
Solution 4	Raimundo
Solution 5	bbsimonbb
Solution 6	KRISHNA KESHOB PAUL
Solution 7	Omar AlSaheb

'Javascript Date - set just the date, ignoring time?

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