Issues removing words from a list in Python

Question

I'm building a Wordle solver. Basically removing words from a list, if they don't have specific characters, or don't have them at specific locations. I'm not concerned about the statistics for optimal choices yet.

When I run the below code (I think all relevant sections are included), my output is clear that it found a letter matching position to the 'word of the day'. But then the next iteration, it will choose a word that doesn't have that letter, when it should only select from remaining words.

Are words not actually being removed? Or is there something shadowing a scope I can't find? I've rewritten whole sections, with the exact same problem happening.

#Some imports and reading the word list here. 

def word_compare(word_of_the_day, choice_word):
    results = []
    index = 0
    letters[:] = choice_word
    for letter in letters:
        if letter is word_of_the_day[index]:
            results.append((letter, 2, index))
        elif letter in word_of_the_day:
            results.append((letter, 1, index))
        else:
            results.append((letter, 0, index))
        index += 1
    print("\nIteration %s\nWord of the Day: %s,\nChoice Word: %s,\nResults: %s" % (
        iteration, word_of_the_day, choice_word, results))
    return results


def remove_wrong_words():
    for item in results:
        if item[1] == 0:
            for word in words:
                if item[0] in word:
                    words.remove(word)
    for item in results:
        if item[1] == 2:
            for word in words:
                if word[item[2]] != item[0]:
                    words.remove(word)
    print("Words Remaining: %s" % len(words))
    return words


words, letters = prep([])
# choice_word = best_word_choice()
choice_word = "crane"
iteration = 1
word_of_the_day = random.choice(words)

while True:
    if choice_word == word_of_the_day:
        break
    else:
        words.remove(choice_word)
        results = word_compare(word_of_the_day, choice_word)
        words = remove_wrong_words()
        if len(words) < 10:
            print(words)
        choice_word = random.choice(words)
        iteration += 1

Output I'm getting:

Iteration 1
Word of the Day: stake,
Choice Word: crane,
Results: [('c', 0, 0), ('r', 0, 1), ('a', 2, 2), ('n', 0, 3), ('e', 2, 4)]
Words Remaining: 386

Iteration 2
Word of the Day: stake,
Choice Word: lease,
Results: [('l', 0, 0), ('e', 1, 1), ('a', 2, 2), ('s', 1, 3), ('e', 2, 4)]
Words Remaining: 112

Iteration 3
Word of the Day: stake,
Choice Word: paste,
Results: [('p', 0, 0), ('a', 1, 1), ('s', 1, 2), ('t', 1, 3), ('e', 2, 4)]
Words Remaining: 81

Iteration 4
Word of the Day: stake,
Choice Word: spite,

... This continues for a while until solved. In this output, 'a' is found to be in the correct place (value of 2 in the tuple) on the second iteration. This should remove all words from the list that don't have 'a' as the third character. Instead 'paste' and 'spite' are chosen for later iterations from that same list, instead of having been removed.

Answer 1

I think one of your issues is the following line: if letter is word_of_the_day[index]:. This should be == not is as the latter checks for whether the two objects being compared have the same memory address (i.e. id()), not whether they have the same value. Thus, results will never return a tuple with a value of 2 in position 1, so this means the second for loop in remove_wrong_words won't do anything either. There may be more going on but I'd like a concrete example to run before digging in further.