Is there any way to replace methods in super class without losing the old definition?

Question

I'm trying to replace a function in super class A in order to extend its functionality in B class, but without losing the old definition. So is there any way to force the A::b method to use a new definition from B class? I have experience in Java, so I know it is possible in this language. Expected output is

A::b
B::a
A::a

Current output is

A::b
A::a

#include <iostream>

using namespace std;

class A {
protected:
    static void a() {
        cout << "A::a" << endl;
    }
public:
    void b() {
        cout << "A::b" << endl;
        
        a();
    }
};

class B: public A {
protected:
    static void a() {
        cout << "B::a" << endl;
        A::a();
    }
};

int main()
{
    B b;
    b.b();
    
    return 0;
}

https://godbolt.org/z/dnY5o8WfK

Answer 1

I think you meant to use virtual keyword instead of static as shown below, since static in this context means that there is no implicit this parameter for the non-static member function a.

#include <iostream>

using namespace std;

class A {
protected:
    virtual void a() { //note the virtual keyword
        cout << "A::a" << endl;
    }
public:
    void b() {
        cout << "A::b" << endl;
        
        a();
    }
};

class B: public A {
protected:
    virtual void a() {//note the virtual keyword
        cout << "B::a" << endl;
        A::a();
    }
};

int main()
{
    B b;
    b.b();
    
    return 0;
}

The output of the above program can be seen here:

A::b
B::a
A::a

By using virtual we're making the member function a to be a virtual member funciton.