Is it possible for a program to read itself?

Question

Theoretical question. But let's say I have written an assembly program. I have "labelx:" I want the program to read at this memory address and only this size and print to stdout.

Would it be something like

jmp labelx

And then would i then use the Write syscall , making sure to read from the next instruction from labelx:

mov rsi,rip
mov rdi,0x01
mov rdx,?
mov rax,0x01
syscall

to then output to stdout.

However how would I obtain the size to read itself? Especially if there is a label after the code i want to read or code after. Would I have to manually count the lines?

mov rdx,rip+(bytes*lines)

And then syscall with populated registers for the syscall to write to from rsi to rdi. Being stdout.

Is this Even possible? Would i have to use the read syscall first, as the write system call requires rsi to be allocated memory buffer. However I assumed .text is already allocated memory and is read only. Would I have to allocate onto the stack or heap or a static buffer first before write, if it's even possible in the first place?

I'm using NASM syntax btw. And pretty new to assembly. And just a question.